8^x-3=32^x+2/4-x

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Solution for 8^x-3=32^x+2/4-x equation: 



8^x-3=32^x+2/4-x

We move all terms to the left:

8^x-3-(32^x+2/4-x)=0



Domain of the equation: 4-x)!=0

We move all terms containing x to the left, all other terms to the right

-x)!=-4

x!=-4/1

x!=-4

x∈R



We get rid of parentheses

8^x-32^x+x-3-2/4=0

We multiply all the terms by the denominator


8^x*4-32^x*4+x*4-2-3*4=0

We add all the numbers together, and all the variables

8^x*4-32^x*4+x*4-14=0

Wy multiply elements

32x-128x+4x-14=0

We add all the numbers together, and all the variables

-92x-14=0

We move all terms containing x to the left, all other terms to the right

-92x=14

x=14/-92

x=-7/46

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